Phrases Analytical Puzzle Previous Year Question Paper and Solution with PDF

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Phrases Analytical Puzzle PYQ

Qus : 1

Statement- I: Out of total of 200 readers, 100 read Indian Express, 120 read Times of India and 50 read Hindu.

Statement - II: Out of a total of 200 readers, 100 read Indian Express, 120 reads Times of India and 50 read neither.

How many people (from the group surveyed) read both Indian Express and Times of India?

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Solution

Qus : 2

Study the information carefully and answer the questions given below:

If we arrange the alphabets in the word "RATE" in the English alphabetical order, word "AERT" is formed. Then the third alphabet from the left in this word is "R". similarly, from the word "OPEN" we get - "ENOP" and the third alphabet from the left is "O". From the word "CHEF" we get - "CEFH" the third alphabet from the left "F". From the word "TOY" we get - "OTY" and the third alphabet from the left is "Y". If we use all these letters, then a meaningful English word "FORTY" can be formed.

Now find which of the following word set DOES NOT give a meaningful word in the similar way.

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Solution

Qus : 3

Rajesh will not go to the concert if Rakesh goes. Rakesh will go to the concert if his dog barks three times.

Based only on the information above, which of the following must be true?

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Solution

Statements Given:

Rajesh will not go to the concert if Rakesh goes.
Rakesh will go to the concert if his dog barks three times.

Logical Interpretation:

If Rakesh goes → Rajesh will not go
If Dog barks 3 times → Rakesh will go

Deduction:

If the dog barks three times, then Rakesh goes. And if Rakesh goes, Rajesh will not go.

✅ Final Answer: If the dog barks three times, Rajesh will not go to the concert.

Qus : 4

Using only 2, 5, 10, 25 and 50 paise coins, the smallest number of coins required to pay exactly 79 paise, 66 paise and Re 1.01 to three different persons is

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Solution

Coins For 79 Paise :

25 paise × 3 coins + 2 paise × 2 coins Total number of coins for 79 paise = 5

Coins For 66 Paise :

50 paise × 1 coin + 10 paise × 1 coin + 2 paise × 3 coin

Total number of coins for 66 paise = 5 coins

For 1.01 Paise :

50 paise × 1 coin + 25 paise × 1 coin + 10 paise × 2 coin + 2 paise × 3 coin

Total number of coins for Rs. 1.01 paise = 7 coins

So, total coins used = (5 + 5 + 7) coins

= 17 coins

Ans.(A) (because given that smallest no. of coin)

Qus : 5

Kha-kha is an obscure island which is inhabited by two types of people : the “Yes” type and the “No” type. Native of type ‘Yes' ask only questions the right answer to which is ‘Yes' while those of type ‘No' ask only questions the right answer to which is ‘No'. For example the ‘Yes' type will ask questions like “Is 2 plus 2 equal to 4?” While the “No” type will ask questions like “Is 2 plus 2 equal to 5?”. The following question is based on your visit to the island Kha-Kha.

Kevin and Kumar are brothers from the island. Kumar asks you. Is at least one of us is of type ‘No' ? You can conclude that

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Solution

Qus : 6

Each of the five people K, L, M, P and Q is of a different weight. It is known that the number of people heavier than P is the same as the number of people lighter than Q. L is the heaviest and K is not the lightest. Who is the lightest?

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Solution

Qus : 7

Some friends planned to contribute equally to jointly buy a CD player. However, two of them decided to withdraw at the last minute. As a result, each of the others had to shell out one rupee more than what they had planned for. If the price (in Rs.) of the CD player is an integer between 1000 and 1100, find the number of friends who actually contributed?

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Solution

We will assume the friends to be x and the contribution they are going to make be y

so,

xy = (x-2)(y+1)

= xy - 2y + x - 2

x = 2(y+1)

Here are the possible values of y,x and yx:

y = 21,22,23,24

x = 44,46,48,50

xy = 920, 1012,1104,1200

1000 < xy < 1100 (y,x)

= (22,46)

which will be x = 46

So the number of friends would be x -2 = 44

Qus : 8

Two persons S and M have made the following statements among themselves.

S says that I am certainly not over 40 years.

M says that I am 38 years and you are at least 5 year old than me.

S says you are at least 39 years.

If all the above statements are wrong, what are the ages of M and S?

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Solution

Qus : 9

Each family in a locality has at most two adults, and no family has fewer than 3 children. Considering all the families together, there are more adults than boys, more boys than girls, and more girls than families. Then the minimum possible number of families in the locality is

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Solution

Let n_f be number of families, n_g be number of girls, n_b be number of boys and n_abe number of adults.

number of adults more than number of boys, number of boys more than number of girls and number of girls more than number of families.

hence we have, n_a > n_b > n_g > n_f ..........................(1)

we check the above relation (1) with different values for number of families, starting with n_f= 1

Let n_f= 1 , then n_b + n_g= 3 , if n_g =2 then n_b = 1 . But number of boys is greater than number of girls.
due to this contradiction, n_f ≠ 1

Let n_f= 2 , then n_b + n_g= 6 , if n_g =3 then n_b = 3 . But number of boys is greater than number of girls.
due to this contradiction, n_f ≠ 2

Let n_f= 3 , then n_b + n_g= 9 , if n_g =4 then n_b = 5 . number of adults n_a = 6.

hence the relation n_a > n_b > n_g > n_fis satisfied for the above numbers, 6>5>4>3
hence minimum number of families is 3

Qus : 10

caterpillar crawls up a pole of 75 inches high standing from the ground. Each day is crawls up 5 inches and each night it slides down 4 inches. When will it reach the top of the pole?

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Solution

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